Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • From a moving point P on <img alt="\mathrm{x^{2} + y^{2} = 4}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bx%5E%7B2%7D%20&plus;%20y%5E%7B2%7D%20%

From a moving point P on \mathrm{x^{2} + y^{2} = 4} tangent PA and PB are drawn to \mathrm{x^{2} + y^{2} = a^{2}} then the locus of the circumcentre of triangle PAB is \mathrm{(|a| < 2)}

Option: 1

\mathrm{x^2+y^2=a^2+4}


Option: 2

\mathrm{x^2+y^2=4-a^2}


Option: 3

\mathrm{x^2+y^2=1}


Option: 4

none of these


Answers (1)

best_answer

Clearly PO is the diameter of circumcircle.

Hence locus of circumcentre is \mathrm{x^{2}+ y^{2} = 1.}

 

Posted by

Pankaj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question