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  • Give answer! An amount of 1.00 g of a gaseous compound of Boron and Hydrogen occupies 0.820 litre at 1.00 atm and at 3oC. The compound is (R = 0.0820 liter atm mole-1 K-1; at. wt: H = 1.0, B = 10.8)

An amount of 1.00 g of a gaseous compound of Boron and Hydrogen occupies 0.820 litre at 1.00 atm and at 3oC. The compound is (R = 0.0820 liter atm mole-1 K-1; at. wt: H = 1.0, B = 10.8) 

  • Option 1)

    BH3

  • Option 2)

    B4H10

  • Option 3)

    B2H6

  • Option 4)

    B3H12

 

Answers (1)

best_answer

As we learnt in 

Ideal Gas Law -

PV=nRT

- wherein

P - Pressure

V - Volume

n - No. of Moles

R - Gas Constant

T - Temperature

 

PV =nRT

PV =\frac{1}{M}RT


Option 1)

BH3

Incorrect

Option 2)

B4H10

Incorrect

Option 3)

B2H6

Correct

Option 4)

B3H12

Incorrect

Posted by

Aadil

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