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The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t=\sqrt{x}+3. The displacement of the particle when its velocity is zero, will be 

  • Option 1)

    2m

  • Option 2)

    4m

  • Option 3)

    Zero

  • Option 4)

    6m

 

Answers (1)

best_answer

As learnt in

Velocity -

Rate of change of displacement with time.

Formula V=frac{displacement}{time}

- wherein

E.g. A car moving along a straight line. It moves from O to P (60 m)  in 18 sec and returns from P to O (60 m) in 60 sec
Find velocity.

 

 Given, t=\sqrt{x}+3\ \ \ \ \Rightarrow \sqrt{x}= t-3

x= \left ( t-3 \right )^{2}\ \ \ \ \Rightarrow \frac{dx}{dt} = 2\left ( t-3 \right )=0

t= 3

\therefore x= \left ( 3-3 \right )^{2}\ \ \ \Rightarrow x=0


Option 1)

2m

This option is incorrect

Option 2)

4m

This option is incorrect

Option 3)

Zero

This option is correct

Option 4)

6m

This option is incorrect

Posted by

divya.saini

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