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When a mass M is attached to the spring of force constant K, then the spring stretches by l. If the mass oscillates with amplitude l, what will be the maximum potential energy stored in the spring

  • Option 1)

    \frac{Kl}{2}

  • Option 2)

    2Kl

  • Option 3)

    \frac{1}{2} Mgl

  • Option 4)

    Mgl

 

Answers (1)

best_answer

Mg = kl \Rightarrow U_{max} = \frac{1}{2}k(2l)^{2} = 2kl


Option 1)

\frac{Kl}{2}

This is incorrect.

Option 2)

2Kl

This is correct.

Option 3)

\frac{1}{2} Mgl

This is incorrect.

Option 4)

Mgl

This is incorrect.

Posted by

divya.saini

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