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  • Given below is a graph of is <img alt="\mathrm{\log C_0}" src="

Given below is a graph of \mathrm{\log t_{1 / 2}} is \mathrm{\log C_0}, what will be the order of the reaction?

t_{1 / 2}=\text { Half-life of } \mathrm{Rx^n}

Option: 1

0


Option: 2

1


Option: 3

2


Option: 4

None of these


Answers (1)

best_answer

\because For zeroth order Reaction

\begin{aligned} \mathrm{t_{1 / 2}} & =\mathrm{\frac{c_0}{2 k}=k^{\prime} c_0} \\ \mathrm{\log t_{1 / 2}} & =\mathrm{\log k^{\prime}+1 \log c_0} \end{aligned}

for first order Reaction: \mathrm{t_{1 / 2}=\frac{0.693}{k}}

For second order Reaction: \mathrm{t_{1 / 2}=\frac{1}{k C_0}}

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Sayak

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