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  • Given below the reaction; the current efficiency of the process is 75%. What volume the gas produced at <img alt="27^{\circ} \mathrm{C}" src="https://entrancecorner.oncodecogs.com/gif.latex?27%5E%7

Given below the reaction; the current efficiency of the process is 75%. What volume the gas produced at 27^{\circ} \mathrm{C} and 735 torr, if current of 0.7 amp passed through 93.8 min ?
\mathrm{ 2 \mathrm{CH}_3 \mathrm{COO}^{-} \rightarrow \mathrm{C}_2 \mathrm{H}_6(\mathrm{~g})+2 \mathrm{CO}_2(\mathrm{~g})+2 e^{-} }

Option: 1

2.66 l


Option: 2

1.14 l


Option: 3

3.67 l


Option: 4

1.71 l


Answers (1)

best_answer

Equiralents of  \mathrm{CO}_2  produced
\mathrm{ \frac{(I \times n) \times t}{96500} }

\mathrm{ =\frac{0.7 \times 0.75 \times 93.8 \times 60}{96500} }

\mathrm{ =0.030 }

\mathrm{moles ~of \mathrm{~CO}_2~(n=1) ~produced =0.030 }

\mathrm{ moles ~of \mathrm{~C}_2 \mathrm{H}_6~(n=2) ~produced =\frac{0.030}{2}=0.015 }

Total moles of gases produced = 0.045

\mathrm{ V_{\text {gases }}=\frac{n R T}{P}=\frac{0.045 \times 0.0821 \times 300}{\left(\frac{735}{760}\right)} }

\mathrm{V_{\text {gas }}=1.14 \text { litre } }

Posted by

rishi.raj

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