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  • Gravitation potential due to the uniform ring having mass M at the centre of the ring isOption: 1 <img alt="-\frac{GM}{a^2}" src="https://learn.caree

Gravitation potential due to the uniform ring having mass M at the centre of the ring is

Option: 1

-\frac{GM}{a^2}


Option: 2

\frac{GM}{a^2}


Option: 3

-\frac{GM}{a}


Option: 4

zero


Answers (1)

best_answer

As we have learnt,

 

 

Gravitational potential due to Uniform circular ring -

For Uniform circular ring

 

r= distance from ring

a\rightarrow radius of Ring

V\rightarrow Potential 

 

At a point on its Axis 

V=-\frac{GM}{\sqrt{a^{2}+r^{2}}}

At the center 

V=-\frac{GM}{a}

 

 At the centre V = \frac{-GM}{a}[as given in formula]

 

Posted by

Kuldeep Maurya

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