Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Half -life for a radioactive isotope of Indium is .The time required to fall

Half -life for a radioactive isotope of Indium is 69300\, \mathrm{sec}.The time required to fall the rate of decay to \left(\frac{1}{10}\right)^{\text {th }} of its initial value is = ?

Option: 1

2.303 \times 10^{5} \mathrm{~s}


Option: 2

4.606 \times 10^{5} s


Option: 3

2.303 \times 10^{4} s


Option: 4

4.6 \times 10^{4}s


Answers (1)

best_answer

\mathrm{\lambda=\frac{0.693}{t_{1 / 2}}=\frac{0.693}{69300}=10^{-5} \mathrm{~s}^{-1}}
\mathrm{t=\frac{1}{\lambda} \ln \left(\frac{R_{0}}{R}\right)=\frac{1}{10^{-5}} \ln (10)}

\mathrm{ t=2.303 \times 10^{5} s=230300 \, s}

Posted by

sudhir.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: NIT Rourkela cut-offs for CSE, chemical engineering drop; last years' closing ranks
anam-khan

JEE Main 2025 Live: NTA exam city slip at jeemain.nta.nic.in soon; session 1 schedule
anam-khan

JEE Main 2025 schedule out for session 1; paper 1 from January 22

Latest Question