Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Half life for the zero order reaction <img alt="\mathrm{PCl}_5(g) \rightarrow Cl(g) +\mathrm{Cl}_2(\mathrm{~g})" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BPCl%7D_5%28g%29%20%

Half life for the zero order reaction \mathrm{PCl}_5(g) \rightarrow Cl(g) +\mathrm{Cl}_2(\mathrm{~g})and half life for the first order reaction \mathrm{R(g) \rightarrow P(g)+Q(g)} are equal. If completion time for the zero order reaction is 12 min, then calculate the rate constant \mathrm{(in \ hr^{-1} )} for the reaction \mathrm{R(g) \rightarrow P(g)+Q(g)} ?

Option: 1

6.93


Option: 2

12.86


Option: 3

6


Option: 4

12


Answers (1)

best_answer

\mathrm{\text { For zeroth order, } 2\left(t_{1 / 2}\right)_0=\tau_{\text {complete }}}

\mathrm{\left(t_{1 / 2}\right)_0=6 \mathrm{~min}=\frac{6}{60} \mathrm{hr}}

\mathrm{\text { For First order, }\left(t_{1 / 2}\right)_1=\frac{0.693}{k}}

\mathrm{\begin{aligned} \because\left(t_{1 / 2}\right)_1 & =\left(t_{1 / 2}\right)_0 \\ \frac{0.693}{k} & =\frac{6}{60} h_r \\ k & =6.93 \mathrm{hr}^{-1} \end{aligned}}

Posted by

Rishi

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 final answer key likely in February 2nd week; result date, marking scheme
anam-khan

JEE Mains 2025 Answer key (OUT) LIVE: Session 1 result by February 12 on jeemain.nta.nic.in; cut-off
anam-khan

JEE Main Marks vs Percentile 2025: How many marks do you need to score 95+ percentile?

Latest Question