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\mathrm{a^2 x} Half-life  \mathrm{ t_{3 / 2}}   =  constant confirms that the reaction is of 

Option: 1

Zero order 


Option: 2

First order


Option: 3

Second order 


Option: 4

Third order


Answers (1)

best_answer

\mathrm{\mathrm{t}_{1 / 2} \propto \frac{1}{a^{(n-1)}}} 
Since it is given that  \mathrm{a^2 x}  Half-life \mathrm{t_{3 / 2}=}  constant It may be said that -
\mathrm{ t_{1 / 2} \propto \frac{1}{a^2}}


\mathrm{ \Rightarrow n-1=2 \\ }

\mathrm{ \Rightarrow n=3 }.
 

Posted by

Ritika Kankaria

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