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  • Help me answer: A machine gun fires a bullet of mass 40g with a velocity 1200 ms-1 The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

A machine gun fires a bullet of mass 40g with a velocity 1200 ms-1 The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

  • Option 1)

    one

  • Option 2)

    four

  • Option 3)

    two

  • Option 4)

    three

 

Answers (1)

best_answer

As we learnt in

Newton's 2nd Law -

F\propto \frac{dp}{dt}

F=\tfrac{kdp}{dt} 

F=\tfrac{d\left (mv \right )}{dt} 

F=\tfrac{m\left (dv \right )}{dt}

\frac{dv}{dt}=a

Therefore  F=ma

- wherein

K=1 in C.G.S & S.I

 

 

 

Suppose he can fire n bullets per second

Force = Change in momentum per second

144= n\times \left ( \frac{40}{1000} \right )\times \left ( 1200 \right )

or\: \:\: \: n= \frac{144\times 1000}{40\times 1200}

or\: \:\: \: n= 3

Correct option is 4.


Option 1)

one

This is an incorrect option.

Option 2)

four

This is an incorrect option.

Option 3)

two

This is an incorrect option.

Option 4)

three

This is the correct option.

Posted by

divya.saini

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