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  • Help me answer: - Given for awith usual notation. Ifthen the ordered triad has a value : - Trigonometry - JEE Main

Given \frac{b+c}{11}=\frac{c+a}{12}=\frac{a+b}{13}  for a \Delta ABC with usual notation. 

If \frac{\cos A}{\alpha }=\frac{\cos B}{\beta }=\frac{\cos C}{\gamma }, then the ordered triad (\alpha ,\beta ,\gamma ) has a value :

  • Option 1)

    (5,12,13)

  • Option 2)

    (7,19,25)

  • Option 3)

    (19,7,25)

  • Option 4)

    (3,4,5)

Answers (1)

best_answer

 

Cosine Rule - Cosine Rule - null

b+c=11\lambda

a+c=12\lambda

a+b=13\lambda

=>a=7\lambda \: , \: b=6\lambda \: ,\: c=5\lambda

Using Cosine Formula,

\cos A=\frac{1}{5}\: ,\: \cos B=\frac{19}{35}\: ,\: \cos C=\frac{5}{7}

\alpha :\beta :\gamma =7:19:25


Option 1)

(5,12,13)

Option 2)

(7,19,25)

Option 3)

(19,7,25)

Option 4)

(3,4,5)

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