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In a double-slit experiment, green light (5303 \AA ) falls on a double slit having a separation of 19.44 \mu m and a width of 4.05 \mu m . The number of bright fringes between the first and the second diffraction minima is :

  • Option 1)

    04

  • Option 2)

    10

  • Option 3)

    09

  • Option 4)

    05

Answers (1)

best_answer

 

Young Double Slit Experiment -

- wherein

y=\Delta x\cdot \left ( \frac{D}{d} \right )

y= Distance of a point on screen from central maxima

\Delta x= Path difference at that point

 

\lambda =5303A^{\circ}                                                                        

In YDS \rightarrow For diffraction 

For 1st minima

Y_{1}=\frac{D\lambda }{a}\approx 0.24\lambda \times D

For 2nd minima

Y_{2}=\frac{2D\lambda }{a}\approx 0.49\lambda \times D

Now for Interference .

Path difference at A=\frac{dY_{1}}{D}=4.8\lambda

Path difference at B=\frac{dY_{2}}{D}=9.8\lambda

So order of maxima between A & B 

=5,6,7,8,9

So 5 bright fringes will present between A & B. 

 


Option 1)

04

Option 2)

10

Option 3)

09

Option 4)

05

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