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Molal depression constant for water is 1.860C . The freezing point of a 0.05 molal solution of a non-electrolyte in water is

  • Option 1)

    -1.86^{\circ}C

     

     

     

  • Option 2)

    -0.93^{\circ}C

  • Option 3)

    -0.093^{\circ}C

  • Option 4)

    0.93^{\circ}C

 

Answers (1)

best_answer

As we learned

 

Mathematical Expression of Depression in Freezing point -

\Delta T_{f}= K_{f}\: m
 

- wherein

m = molarity of solvent 

K_{f} = cryoscopic  constant

    molal depress const

Units = \frac{K-K_{g}}{mole}

 

 \Delta T_{f}=K_{f}\times molality=1.86\times 0.05 = 0.093^{\circ}C

Thus freezing point ==0-0.093=-0.093C^{\circ}

 

 


Option 1)

-1.86^{\circ}C

 

 

 

Option 2)

-0.93^{\circ}C

Option 3)

-0.093^{\circ}C

Option 4)

0.93^{\circ}C

Posted by

satyajeet

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