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  • Help me please, A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1and that covered in the first 20 seconds is S2,then:

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then:

  • Option 1)

    S2=3S1

  • Option 2)

    S2=4S1

  • Option 3)

    S2=S1

  • Option 4)

    S2=2S1

 

Answers (2)

As learnt in

2nd equation or Position- time equation -

s= ut +frac{1}{2}at^{2}

s ightarrow Displacement

u ightarrowInitial velocity

a ightarrowacceleration

t ightarrow time

 

-

 

 u = 0    t1 = 10 sec    t2 = 20 sec

s = ut +\frac{1}{2}at^{2}

s_{1} = \frac{1}{2}a{t_{1}}^{2}

s_{2} = \frac{1}{2}a{t_{2}}^{2}

\therefore \frac{s_{1}}{s_{2}} =\left ( \frac{t_{1}}{t_{2}} \right )^{2} = \left ( \frac{10}{20} \right )^{2} = \frac{1}{4}

\Rightarrow s_{2} = 4s_{1}


Option 1)

S2=3S1

This option is incorrect

Option 2)

S2=4S1

This option is correct

Option 3)

S2=S1

This option is incorrect

Option 4)

S2=2S1

This option is incorrect

Posted by

subam

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s=

Posted by

ashima

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