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  • Help me please, The compressibility factor for 1 mole of a Vander Waal's gas at 0oC and 100 atm pressure is found to be 0.5 then the Vreal is -

The compressibility factor for 1 mole of a Vander Waal's gas at 0oC and 100 atm pressure is found to be 0.5 then the Vreal is -

  • Option 1)

    0.224 L

  • Option 2)

    0.112 L

  • Option 3)

    22.4 L

  • Option 4)

    11.2 L

 

Answers (1)

As we learnt in 

Compressibility Factor -

Z=Vreal/Videal

-

 

\\* PV_{ideal }= nRT \\* V_{ideal}= \frac{nRT}{P}= \frac{1\times 0.0821\times 273}{100}= 0.224L\\*

Z=\frac{V_{real}}{V_{ideal}}\Rightarrow 0.5= \frac{V_{real}}{0.224}

V_{real}= 0.112L


Option 1)

0.224 L

Incorrect

Option 2)

0.112 L

Correct

Option 3)

22.4 L

Incorrect

Option 4)

11.2 L

Incorrect

Posted by

subam

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