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If \sin\frac{2A}{3} = \frac{1}{6}. Find the value of \sin2A

  • Option 1)

    \frac{11}{27}

  • Option 2)

    \frac{13}{27}

  • Option 3)

    \frac{12}{27}

  • Option 4)

    None of these

 

Answers (1)

best_answer

As we have learnt,

 

Trigonometric Ratios of Submultiples of an Angle -

Trigonometric ratios of submultiples of an angle 2

- wherein

This shows the formulae for one-third angles and their triples.

 

 \sin2A = 3\sin\frac{2A}{3}- 4\sin^3\frac{2A}{3}

                \\*= 3\times\frac{1}{6} - 4\times\frac{1}{216} \\*=\frac{1}2 - \frac{1}{54} = \frac{26}{54} = \frac{13}{54}

 


Option 1)

\frac{11}{27}

Option 2)

\frac{13}{27}

Option 3)

\frac{12}{27}

Option 4)

None of these

Posted by

Himanshu

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