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The moment of inertia of a uniform semicircula  disc of mass M and radius  r about a line  perpendicular to the plane of the disc through the center is :

Option 1)

Mr^{2}

 Option 2)

\frac{1}{2}Mr^{2}
Option 3)

\frac{1}{4}Mr^{2}

 Option 4)

\frac{2}{5}Mr^{2}

Answers (1)

best_answer

As we learnt in

Moment of inertia for disc -

I=\frac{1}{2} MR^{2}

 

- wherein

About an axis perpendicular to the plane of disc & passing through its centre .

 

 We know that moment of inertia of semicircular disc through the centre I=\frac{mr^{2}}{2}


Option 1)

Mr^{2}

This is an incorrect option.

Option 2)

\frac{1}{2}Mr^{2}

This is the correct option.

Option 3)

\frac{1}{4}Mr^{2}

This is an incorrect option.

Option 4)

\frac{2}{5}Mr^{2}

This is an incorrect option.

Posted by

Aadil

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