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  • Help me solve this Two sound waves are given by y = a sin (wt - kx) and y'= b cos (wt - kx). The phase difference between the two waves is

Two sound waves are given by y = a sin (wt - kx) and y' = b cos (wt - kx). The phase difference between the two waves is

  • Option 1)

    \frac{\pi}{2}

  • Option 2)

    \frac{\pi}{4}

  • Option 3)

    \pi

  • Option 4)

    \frac{3\pi}{4}

 

Answers (1)

best_answer

As we learnt in 

Travelling Wave Equation -

y=A \sin \left ( Kx-\omega t \right )
 

- wherein

K=2\pi /\lambda

\omega = \frac{2\pi }{T}

\lambda =  wave length

T = Time period of oscillation

 

 y=asin(\omega t - Kx) and y^{'}=bsin(\omega t - Kx+\frac{\pi}{2})

Phase difference = \frac{\pi}{2}

 


Option 1)

\frac{\pi}{2}

This option is correct.

Option 2)

\frac{\pi}{4}

This option is incorrect.

Option 3)

\pi

This option is incorrect.

Option 4)

\frac{3\pi}{4}

This option is incorrect.

Posted by

Aadil

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