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  • Help me understand! The mean translational K.E. per unit volume E and the pressure P of a perfect gas are related as

The mean translational K.E. per unit volume E and the pressure P of a perfect gas are related as

  • Option 1)

    P=\frac{E}{2V}

  • Option 2)

    P=\frac{2E}{3V}

  • Option 3)

    P=\frac{3}{2}EV

  • Option 4)

    P=\frac{3E}{2V}

 

Answers (1)

best_answer

As we learnt in 

Kinetic energy of a gas due to translation per mole -

E= \frac{3}{2}PV

= \frac{3}{2}RT
 

- wherein

R = Universal gas constant

T = temperature of gas

 

 E=\frac{3}{2}nRT=\frac{3}{2}PV

\therefore P=\frac{2E}{3V}

 


Option 1)

P=\frac{E}{2V}

Incorrect

Option 2)

P=\frac{2E}{3V}

Correct

Option 3)

P=\frac{3}{2}EV

Incorrect

Option 4)

P=\frac{3E}{2V}

Incorrect

Posted by

prateek

View full answer

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