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  • How many atom of calcium will be deposited from a solution of    by a current

How many atom of calcium will be deposited from a solution of  \mathrm{CaCl}_2  by a current $0.35 \mathrm{~mA} flowing for 60 \mathrm{~s}

Option: 1

2.2 \times 10^{20}


Option: 2

1.2 \times 10^{19}


Option: 3

3.2 \times 10^{18}


Option: 4

6.5 \times 10^{18}


Answers (1)

best_answer

i=0.35 \mathrm{~mA}=0.035 \mathrm{~A} \\i=0.35 \mathrm{~mA}=0.035 \mathrm{~A} \\

\mathrm{ \quad t=60 \mathrm{~s} }
\mathrm{ Q=i t \\ }

\mathrm{ Q=i t \\ Q=60 \times 0.035 \\ }

              \mathrm{ Q=2.1 \mathrm{C} }

No. of electron    \mathrm{ =\frac{2.1 \times 6.023 \times 10^{23}}{96500} }
                          \mathrm{ e=13.1 \times 10^{18} \\ }
\mathrm{C a \rightarrow C^{2+}+2 e^{-} }

\mathrm{2 e^{-} } are required to deposits one Ca atom  \mathrm{13.1 \times 10e^{18-} }  will be used to deposite \mathrm{\frac{13.1 \times 10^{18}}{2}=6.5 \times 10^{18} }.

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Divya Prakash Singh

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