Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • How many different four-letter codes can be formed using the letters A, B, C, D, and E if repetition is allowed?Option: 1 825<div class

How many different four-letter codes can be formed using the letters A, B, C, D, and E if repetition is allowed?

Option: 1

825


Option: 2

645


Option: 3

625


Option: 4

785


Answers (1)

best_answer

If repetition is allowed, we can use the concept of combinations with repetition to calculate the number of different four-letter codes that can be formed using the letters A, B, C, D, and E.

For each of the four positions, we have 5 choices (A, B, C, D, or E). Since repetition is allowed, we can choose any of these 5 letters for each position independently.

Therefore, the total number of different four-letter codes with repetition allowed is calculated as:

5 \times 5 \times 5 \times 5=5^4=625.

Hence, there are 625 different four-letter codes that can be formed using the letters A, B, C, D, and E when repetition is allowed.

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 session 2 application correction begins on jeemain.nta.nic.in; edit details by tomorrow
anam-khan

JEE Main 2026 Registration LIVE: Session 2 exam from April 2 to 9; shift timings, admit card, exam pattern
anam-khan

JEE Main 2026 session 2 registration ends today for BTech, BArch; apply at jeemain.nta.nic.in

Latest Question