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How many different four-letter codes can be formed using the letters A, B, C, D, and E if repetition is not allowed?

 

Option: 1

120


Option: 2

100


Option: 3

140


Option: 4

160


Answers (1)

If repetition is not allowed, we can use the concept of permutations to calculate the number of different four-letter codes that can be formed using the letters A, B, C, D, and E.

To determine the number of permutations, we need to consider that for the first position, we have 5 choices (A, B, C, D, or E). For the second position, we have 4 remaining choices, for the third position we have 3 remaining choices, and for the fourth position, we have 2 remaining choices.

Therefore, the total number of different four-letter codes without repetition is calculated as:

5 \times 4 \times 3 \times 2=120.

Hence, there are 120 different four-letter codes that can be formed using the letters A, B, C, D, and E, assuming repetition is not allowed.

Posted by

Ramraj Saini

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