How many different three-digit numbers can be formed using the prime numbers less then 12 if repetition is allowed and ten's position is filled with the square root of n, where n=4?
35
46
62
25
To calculate the number of different three-digit numbers that can be formed using the prime numbers less than 12, with repetition allowed and the ten's position filled with the square root of 4, we can proceed as follows:
The square root of 4 is 2, so for the ten's position, we have only one option, which is 2.
For the hundreds position, we can choose any prime number less than 12. The prime numbers less than 12 are 2, 3, 5, 7, and 11. Since repetition is allowed, we have five options.
For the one's position, we can again choose any prime number less than 12. With repetition allowed, we have five options.
Therefore, the number of different three-digit numbers that can be formed is obtained by multiplying the choices for each position:
Number of choices for the ten's position = 1 (since it is fixed as 2)
Number of choices for the hundreds position = 5 (any of the five prime numbers less than 12)
Number of choices for the one's position = 5 (any of the five prime numbers less than 12)
Total number of different three-digit numbers = Number of choices for the ten's position Number of choices for the hundreds position
Number of choices for the one's position
= 1 5
5
= 25
Therefore, there are 25 different three-digit numbers that can be formed using the prime numbers less than 12, with repetition allowed and the ten's position filled with the square root of 4 (2).
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