How many different three-letter codes can be formed using the letters A, B, C, D, E, F, G, and H if repetition is allowed and first letter is E?
34
10
64
48
If repetition is allowed and the first letter must be "E", there are 8 options for the first position (only "E" can be chosen). For the remaining two positions, there are still 8 options (A, B, C, D, E, F, G, H) since repetition is allowed.
Therefore, the number of different three-letter codes that can be formed with "E" as the first letter, and repetition allowed for the other positions, is calculated by multiplying the number of options for each position:
1 option (E) 8 options 8 options = 64 different three-letter codes.
Thus, there are 64 different three-letter codes that can be formed using the letters A, B, C, D, E, F, G, and H, where repetition is allowed, and the first letter is "E".
Study 40% syllabus and score up to 100% marks in JEE