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How many different three-letter codes can be formed using the letters A, B, C, D, E, F, G, and H if repetition is allowed and first letter is E?

 

Option: 1

34


Option: 2

10


Option: 3

64


Option: 4

48


Answers (1)

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If repetition is allowed and the first letter must be "E", there are 8 options for the first position (only "E" can be chosen). For the remaining two positions, there are still 8 options (A, B, C, D, E, F, G, H) since repetition is allowed.

Therefore, the number of different three-letter codes that can be formed with "E" as the first letter, and repetition allowed for the other positions, is calculated by multiplying the number of options for each position:

1 option (E) \times 8 options \times 8 options = 64 different three-letter codes.

Thus, there are 64 different three-letter codes that can be formed using the letters A, B, C, D, E, F, G, and H, where repetition is allowed, and the first letter is "E".

 

Posted by

Ritika Jonwal

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