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  • How many different three-letter codes can be formed using the letters A, B, C, D, E, F, G, and H if repetition is allowed and second letter is A?  <strong

How many different three-letter codes can be formed using the letters A, B, C, D, E, F, G, and H if repetition is allowed and second letter is A?

 

Option: 1

64


Option: 2

50


Option: 3

94


Option: 4

48


Answers (1)

best_answer

If repetition is allowed and the second letter must be "A", there are 8 options for the first position (A, B, C, D, E, F, G, H). For the second position, there is only 1 option (A) since it must be "A". For the third position, there are again 8 options.

Therefore, the number of different three-letter codes that can be formed with "A" as the second letter, and repetition allowed for the other positions, is calculated by multiplying the number of options for each position:

8 options \times 1 option (A) \times 8 options = 64 different three-letter codes.

Thus, there are 64 different three-letter codes that can be formed using the letters A, B, C, D, E, F, G, and H, where repetition is allowed, and the second letter is "A".

 

Posted by

shivangi.bhatnagar

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