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How many different three-letter codes can be formed using the letters A, B, C, D, E, F, G, and H if repetition is not allowed and first letter is G?

Option: 1

64


Option: 2

42


Option: 3

44


Option: 4

48


Answers (1)

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If repetition is not allowed and the first letter must be "G", there are 7 options remaining for the second letter (excluding G), and 6 options remaining for the third letter (excluding G and the second letter).

Therefore, the number of different three-letter codes that can be formed with "G" as the first letter, without repetition, is calculated by multiplying the number of options for each position:

1 option (G) \times 7 options \times 6 options = 42 different three-letter codes.

Thus, there are 42 different three-letter codes that can be formed using the letters A, B, C, D, E, F, G, and H, where repetition is not allowed, and the first letter is "G".

 

Posted by

Ajit Kumar Dubey

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