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  • How many different ways can 5 red, 2 green, and 2 blue bulbs be arranged in a function with 9 sockets?  Option: 1 254<di

How many different ways can 5 red, 2 green, and 2 blue bulbs be arranged in a function with 9 sockets?

 

Option: 1

254


Option: 2

125


Option: 3

156

 


Option: 4

625


Answers (1)

best_answer

Given that,

There are 5 red, 2 green, and 2 blue bulbs arranged in a function with 9 sockets.

Using the theorem,

\frac{n!}{n_1!\times n_2!\times n_3!.....n_n!}

Thus, 

\frac{9!}{5!\times 2!\times 2!}=756

Therefore, the number of ways the bulbs are arranged in 756 ways.

Posted by

Sanket Gandhi

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