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The work done in placing a charge of  8\times 10^{-18} coulomb on a condenser of capacity 100 micro- farad is

  • Option 1)

    16\times 10 ^{-32} joule

  • Option 2)

    3.1\times 10 ^{-26} joule

  • Option 3)

    4\times 10 ^{-10} joule

  • Option 4)

    32\times 10 ^{-32} joule

 

Answers (2)

best_answer

As we learnt in

Energy Stored -

U=\frac{1}{2}CV^{2}=\frac{1}{2}QV=\frac{Q^{2}}{2C}

-

 

 Energy of condenser

= \frac{1}{2}\frac{Q^{2}}{C}= \frac{1}{2}\times \frac{\left ( 8\times 10^{-18} \right )^{2}}{100\times 10^{-6}}= 32\times 10^{-32}J


Option 1)

16\times 10 ^{-32} joule

Incorrect

Option 2)

3.1\times 10 ^{-26} joule

Incorrect

Option 3)

4\times 10 ^{-10} joule

Incorrect

Option 4)

32\times 10 ^{-32} joule

Correct

Posted by

Aadil

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