Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Let $f(x)=5-|x-2|$ and $g(x)=|x+1|$ ,

$x\epsilon R$ . If $f(x)$ attains maximum value at $\alpha$ and $g(x)$ attains minimum

value at $\beta$ , then

$\lim_{x\rightarrow -\alpha \beta }\frac{(x-1)(x^{2}-5x+6)}{x^{2}-6x+8}$ is equal to :

Option 1)
$1/2$

Option 2)
$-3/2$

Option 3)
$-1/2$

Option 4)
$3/2$

Answers (1)

best_answer

Maxima of $f(x)$ occured at $x=2$ i.e. $\alpha =2$

Minima of $g(x)$ occured at $x=-1$ i.e. $\beta =-1$

$\therefore$ $\lim_{x\rightarrow 2}\frac{(x-1)(x-2)(x-3)}{(x-2)(x-4)}=\frac{1}{2}$

Option 1)

$1/2$

Option 2)

$-3/2$

Option 3)

$-1/2$

Option 4)

$3/2$

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: NTA directs non-Aadhaar applicants to submit photo verification certificate by January 7

anam-khan

Jharkhand CM inaugurates free coaching institute for tribal medical, engineering students

anam-khan

JEE Main 2026: IIT Roorkee’s ECE emerges as top choice after CSE; closing rank rises

Latest Question