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  • How to solve this problem- - States of matter - JEE Main

 At low pressures (For 1 mole), the Vander Waal’s equation is written as -  

\left [ p + \frac{a}{V^{2}} \right ] V = RT

The compressibility factor is then equal to :

  • Option 1)

    \left (1 - \frac{a}{RTV} \right )

  • Option 2)

    \left (1 - \frac{RTV}{a} \right )

  • Option 3)

    \left (1 + \frac{a}{RTV} \right )

  • Option 4)

    \left (1 + \frac{RTV}{a} \right )

 

Answers (1)

As we learnt in 

Compressibility Factor -

at  low pressures, all gases have Z less than 1.

-

\left ( P+\frac{a}{V^{2}} \right )\left ( V \right )= RT

PV+\frac{a}{V}= RT

\frac{PV}{RT}=1-\frac{a}{VRT}

 


Option 1)

\left (1 - \frac{a}{RTV} \right )

Correct

Option 2)

\left (1 - \frac{RTV}{a} \right )

Incorrect

Option 3)

\left (1 + \frac{a}{RTV} \right )

Incorrect

Option 4)

\left (1 + \frac{RTV}{a} \right )

Incorrect

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subam

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