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  • How to solve this problem- - Three Dimensional Geometry - JEE Main

The intersection of the spheres x^{2}+y^{2}+z^{2}+7x-2y-z=13 and x^{2}+y^{2}+z^{2}-3x+3y+4z=8  s the same as the intersection of one of the sphere and the plane

  • Option 1)

    x-y-2z=1

  • Option 2)

    x-2y-z=1

  • Option 3)

    x-y-z=1

  • Option 4)

    2x-y-z=1

 

Answers (1)

best_answer

As we learnt in 

General equation (cartesian form ) -

ax+by+cz+d= 0

-

 

 Intersection of spheres will give a  plane S_{1}-S_{2}= 0

We get 2x-y-z=1


Option 1)

x-y-2z=1

Incorrect Option

Option 2)

x-2y-z=1

Incorrect Option

Option 3)

x-y-z=1

Incorrect Option

Option 4)

2x-y-z=1

Correct Option

Posted by

divya.saini

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