Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I have a doubt, kindly clarify. If 3 gm of glucose (mol. wt. 180) is dissolved in 60 gm of water at 150C . Then the osmotic pressure of this solution will be

If 3 gm of glucose (mol. wt. 180) is dissolved in 60 gm of water at 150C . Then the osmotic pressure of this solution will be

  • Option 1)

    0.34 atm

  • Option 2)

    0.65 atm

  • Option 3)

    6.57 atm

  • Option 4)

    5.57 atm

 

Answers (1)

best_answer

As we learned 

 

Mathematical Expression for Osmotic Pressure -

\pi =CRT
 

- wherein

\pi = Representation of osmotic pressure.

C =Concentration\ of\ Solution

R =Gas \: constant= 0.0821\frac{atm.lit}{mol.k}

T=Temp. \: in\: kelvin

 

 \pi = CRT =\frac{3\times 1000}{180\times 60}\times 0.0821\times 288=6.56atm

 


Option 1)

0.34 atm

Option 2)

0.65 atm

Option 3)

6.57 atm

Option 4)

5.57 atm

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 Exam City Slip LIVE: NTA session 2 test centre allotment soon; admit card date
anam-khan

JEE Main 2026: NTA reopens Session 2 registration; apply by March 13 at jeemain.nta.nic.in
anam-khan

JEE Mains 2026 LIVE: NTA session 2 city slip soon; admit card, exam dates, here's how to prepare

Latest Question