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  • I have a doubt, kindly clarify. - Oscillations and Waves - JEE Main-4

A clock which keeps correct time a 20ºC is subjected to 40ºC. If the coefficent of explansion is 12\times 10^{-6} / ºC. How much it will gain or loose.

  • Option 1)

    10.3 sec / day

  • Option 2)

    20.6 sec/day

  • Option 3)

    5sec/day

  • Option 4)

    20min/day

 

Answers (1)

\frac{\Delta T}{T} = \frac{1}{2}\alpha \Delta \theta = \frac{1}{2} \times 12 \times 10^{-6}\times (40-20)\times 86400 = 10.3 sec/day

 

Effect of temperature on time period of Simple Pendulum -

\frac{\Delta T}{T} = \frac{1}{2}\alpha \Delta \Theta       [Formula]

\Delta T     \rightarrow     change in Temp

T        \rightarrow     Time Period

\Delta \Theta    \rightarrow    change in Temp

\alpha         \rightarrow  Coefficient of Temp

 

- wherein

l_{0} =     Initial Length    

l =     Final Length of wire

 

 


Option 1)

10.3 sec / day

This is correct.

Option 2)

20.6 sec/day

This is incorrect.

Option 3)

5sec/day

This is incorrect.

Option 4)

20min/day

This is incorrect.

Posted by

Vakul

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