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Boron cannot form which one of the following anions?

  • Option 1)

    BF_{6}^{3-}\;

  • Option 2)

    \; BH_{4}^{-}\; \;

  • Option 3)

    \; B(OH)_{4}^{-}\;

  • Option 4)

    \; BO_{2}^{-}

 

Answers (1)

best_answer

As we learned in

Oxidation state of boron family -

Boron show +3 covalence, this tendency decreases down the group, other members have +3 oxidation state form ionic compounds.

- wherein

Lower elements also show +1 ionic state due to inert pair effect. E.g. Tl+, Ga+

 

 Boron cannot expand its octet due to non availability of d-orbitals. Maximum covalence cannot exceed 4.


Option 1)

BF_{6}^{3-}\;

This option is correct.

Option 2)

\; BH_{4}^{-}\; \;

This option is incorrect.

Option 3)

\; B(OH)_{4}^{-}\;

This option is incorrect.

Option 4)

\; BO_{2}^{-}

This option is incorrect.

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Plabita

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