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  • I need help with If 0.15g of a solute dissolved in 15g of solvent is boiled at a temperature higher by 0.2160C than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is 2.160C ) is

If 0.15g of a solute dissolved in 15g of solvent is boiled at a temperature higher by  0.2160C than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is  2.160C ) is

  • Option 1)

    1.01

  • Option 2)

    10

  • Option 3)

    10.1

  • Option 4)

    100

 

Answers (1)

As we learned 

 

Mathematical Expression -

\Delta T_{b}= K_{b}\: m

Unis of K_{b}=\frac{K-K_{g}}{mole}

\Delta T_{b}= Elevation\: in \: boiling\: point
 

- wherein

K_{b}= Boiling \: point \: elevation \: constant

m= molality

 

 m=\frac{K_{b}\times w\times 1000}{\Delta T_{b}\times W}=\frac{2.16 \times 0.15 \times 1000}{0.216\times 15}=100

 

 


Option 1)

1.01

Option 2)

10

Option 3)

10.1

Option 4)

100

Posted by

Vakul

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