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The number of solutions of \sin 3x=\cos 2x, in the interval \left ( \frac{\pi }{2},\pi \right ) is :

  • Option 1)

    1

  • Option 2)

    2

  • Option 3)

    3

  • Option 4)

    4

 

Answers (2)

best_answer

As we learned,

 

Graph of Trigonometric Ratios -

Graph of Trigonometric Ratios

- wherein

This is the graph of y = \sin x

 

 and

 

Graph of Trigonometric Ratios -

Graph 2

- wherein

This is the graph of y = \cos x

 

 

Let's look at the graphs.

There is only one solution.


Option 1)

1

Option 2)

2

Option 3)

3

Option 4)

4

Posted by

Himanshu

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