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Let \vec{u}=\hat{i}+\hat{j},\; \; \vec{v}=\hat{i}-\hat{j}\; and\; \vec{w}=\hat{i}+2\hat{j}+3\hat{k}. If \hat{n} is a unit vector such that \vec{u}\cdot \hat{n}=0 and \vec{v}\cdot \hat{n}=0, then \left |\vec{w}\cdot \vec{n} \right |  is equal to

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As we learnt in 

Vector Product of two vectors(cross product) -

If \vec{a} and \vec{b} are two vectors and \Theta is the angle between them , then \vec{a}\times \vec{b}=\left |\vec{a} \left | \right |\vec{b} \right |Sin\Theta \hat{n}

- wherein

\hat{n} is unit vector perpendicular to both \vec{a} \: and \: \vec{b}

 

 

Scalar Product of two vectors (dot product) -

\vec{a}\vec{b}=\left | a \right |\left | b \right |Cos\theta

- wherein

\Theta is the angle between the vectors\vec{a}\: and\:\vec{b}

 

 Since \vec{n} is perpendicular to \vec{u} \ and \ \vec{v}\vec{u} \times \vec{v} =\begin{vmatrix} \hat i & \hat j & \hat k\\ 1 & 1 & 0 \\ 1 & -1 & 0 \end{vmatrix} = -2 \hat k

 

Unit vector of \vec{u} \times \vec{v} =\hat{k}

Now, \begin{vmatrix} \hat w. \hat n \end{vmatrix} =3


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