Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Ideal Gas Law
A certain amount of helium gas occupies a volume of $\mathrm{0.04 \mathrm{~m}^3}$ at a temperature of $\mathrm{300 \mathrm{~K}}$ and a pressure of $\mathrm{3 \mathrm{~atm}}$ . Calculate the number of moles of helium gas present.

Option: 1
$0.005 \: \mathrm{moles}$

Option: 2
$1.000 \: \mathrm{moles}$

Option: 3
$5.00 \: \mathrm{moles}$

Option: 4
$21.00 \: \mathrm{moles}$

Answers (1)

best_answer

Given data:

Volume, $\mathrm{V=0.04 \mathrm{~m}^3}$

Temperature, $\mathrm{T=300 \mathrm{~K}}$

Pressure, $\mathrm{P=3 \mathrm{~atm}}$

The ideal gas law equation is:

$\mathrm{ P V=\eta R T }$

Solving for the number of moles, $\eta$ :

$\mathrm{ \eta =\frac{P V}{R T} }$

Plugging in the values and the ideal gas constant $\mathrm{ R=8.314 \mathrm{~J} / \mathrm{mol} \mathrm{K}: }$

$\mathrm{ \eta =\frac{(3 \mathrm{~atm}) \cdot\left(0.04 \mathrm{~m}^3\right)}{(8.314 \mathrm{~J} / \mathrm{mol} \mathrm{K}) \cdot(300 \mathrm{~K})} }$

$\mathrm{\eta \approx 0.005 \mathrm{moles}}$

Therefore ,the correct option is 1

Posted by

Rakesh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Trending Articles/News

anam-khan

JEE Main 2026 Registration LIVE: NTA session 1 form link at jeemain.nta.nic.in; application deadline

anam-khan

JEE 2026: IIT admissions show major shift toward AI, data science, away from core engineering courses

anam-khan

JEE Main 2026: NIT Delhi cut-offs for BTech courses show ever-increasing demands for AI, computer skills

Latest Question