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Identify correct form of gravitational law

Option: 1

F= \frac{-Gm_1m_2}{r^2}


Option: 2

\overrightarrow{F}= \frac{-Gm_1m_2}{r^2}


Option: 3

\overrightarrow{F}= \frac{-Gm_1m_2}{r^3}\hat{r}


Option: 4

\overrightarrow{F}= \frac{-Gm_1m_2}{r^3}\overrightarrow{r}


Answers (1)

best_answer

As we learnt

 

Vector form of formula -

 

\vec{F}_{12}=\frac{-Gm_1m_2}{r^{2}}(\hat{r}_{21})

\vec{F}_{12}=\frac{-Gm_1m_2}{r^{3}}(\vec{r}_{21})

\hat{r}_{21}\rightarrow  Positive vector

 

- wherein

\hat{r}_{12}=-\hat{r}_{21}

So, \vec{F}_{12}=-\vec{F}_{21}

 

 

 

Posted by

Anam Khan

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