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Identify the compound from the Haworth projection shown below:

 

Option: 1

\mathrm{\alpha-D-(+) \text { glucopyranose }}


Option: 2

\mathrm{\beta-D-(+) \text { glucopyranose }}


Option: 3

\mathrm{\alpha-D-(+)-g l u c o f u r a n o s e}


Option: 4

\mathrm{\beta-D-(+)-\text { Glucose }}


Answers (1)

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The \mathrm{\alpha} and \mathrm{\beta} forms of glucose can be represented as a six-membered ring called pyranose, resembling the organic

compound pyran. The position of \mathrm{\mathrm{OH}} group at anomeric carbon determines whether it is \mathrm{\alpha} or \mathrm{\beta} glucopyranose where alpha

stands for down \mathrm{\mathrm{OH}} group and beta for up \mathrm{\mathrm{OH}}group.

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