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  • <img alt="\mathrm{E}^{0}_{\mathrm{Cu}^{2+} \mid \mathrm{Cu}}=+0.34 \mathrm{~V}" src="/latex-image/?%5Cmathrm%7BE%7D%5E%7B0%7D_%7B

\mathrm{E}^{0}_{\mathrm{Cu}^{2+} \mid \mathrm{Cu}}=+0.34 \mathrm{~V} \mathrm{E}_{\mathrm{Zn}^{2+} \mid \mathrm{Zn}}^{\mathrm{o}}=-0.76 \mathrm{~V} Identify the incorrect statement from the options below for the above cell:
Option: 1 If Eext > 1.1 V, e- flows from Cu to Zn
Option: 2 If Eext > 1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode
Option: 3 If Eext < 1.1 V Zn dissolves at anode and Cu deposits at cathode
Option: 4 If Eext = 1.1 V, no flow of e- or current occurs

Answers (1)

best_answer

We know,

\mathrm{E}^\textup{o}_{\text {cell }}=\mathrm{E}^\textup{o}_{\text {right }}-\mathrm{E}^\textup{o}_{\text {left }}

\mathrm{E}_{\mathrm{cell}}^{\mathrm{o}}=0.34-(-0.76)

\mathrm{E}_{\mathrm{cell}}^{\mathrm{o}}=1.10 \textup{ volt}

Incorrect statement - If Eext > 1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode

Therefore, the correct option is (2).

Posted by

Kuldeep Maurya

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