Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If a and b are real numbers between 0 and 1 such that the points (a, 1), (1,b) and (0,0) form an equilateral triangle, then <img alt="\mathrm{2(a+b)-a b}" src="https://entrancecorner.oncodecogs.com

If a and b are real numbers between 0 and 1 such that the points (a, 1), (1,b) and (0,0) form an equilateral triangle, then \mathrm{2(a+b)-a b} is equal to

Option: 1

-1


Option: 2

0


Option: 3

1


Option: 4

2


Answers (1)

best_answer

The given vertices are P(a,1), Q(1,b) and R(0,0) and the triangle is equilateral. Hence apply the conditions that angle between PR and RQ should be 60^{\circ} and \mathrm{QP = PR}. 

Hence (A) is the correct answer.

 

Posted by

Devendra Khairwa

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: NIT Rourkela cut-offs for CSE, chemical engineering drop; last years' closing ranks
anam-khan

JEE Main 2025 Live: NTA exam city slip at jeemain.nta.nic.in soon; session 1 schedule
anam-khan

JEE Main 2025 schedule out for session 1; paper 1 from January 22

Latest Question