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If a charge q is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through the flat surface would be :

Option: 1

\mathrm{\frac{q}{\in_{0}}}


Option: 2

\mathrm{\frac{q}{2\in_{0}}}


Option: 3

\mathrm{\frac{q}{4\in_{0}}}


Option: 4

\mathrm{\frac{q}{2\pi\in_{0}}}


Answers (1)

best_answer

Using Gauss's law:
\mathrm{Total\, flux\left ( \phi \right )= \frac{q_{enc}}{\in _{0}}}
\mathrm{\phi_{\text{hemisphere}}= \phi_{\text{curve}}+\phi_{\text{flat}}}
\mathrm{\frac{q}{\in _{0}}= \phi_{\text{curve}}+\phi_{\text{flat}} \ ...(1)}
Consider complete sphere charge kept at centre flux through hemispherical part will be \mathrm{\frac{q}{2\in _{0}}}

\therefore  from equation (1)
\mathrm{\phi_{flat}= \frac{q}{\in_{0}}-\frac{q}{2\in_{0}}= \frac{q}{2\in_{0}}}

The correct answer is (2)


 

Posted by

shivangi.shekhar

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