Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If A is a point on the circle <img alt="\mathrm{x^{2}+y^{2}-4 x+6 y-3=0}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bx%5E%7B2%7D&plus;y%5E%7B2%7D-4%20x&plus;6%20y-3%3D

If A is a point on the circle \mathrm{x^{2}+y^{2}-4 x+6 y-3=0}.  which is farthest from the point \mathrm{(7,2)}, then

Option: 1

(2-2 \sqrt{2},-3-2 \sqrt{2})


Option: 2

(2+2 \sqrt{2},-3-2 \sqrt{2})


Option: 3

\quad(2+2 \sqrt{2},-3+2 \sqrt{2})


Option: 4

\quad(2-2 \sqrt{2},-3+2 \sqrt{2})


Answers (1)

best_answer

Given circle is \mathrm{(x-2)^{2}+(y+3)^{2}=16}
slope of PA  Parametric =  \mathrm{\frac{2+3}{7-2}= 1} equation of line PC is


\mathrm{\frac{x-2}{\frac{1}{\sqrt{2}}}=\frac{y+3}{\frac{1}{\sqrt{2}}}=r \Rightarrow(x, y)=\left(2+\frac{r}{\sqrt{2}},-3+\frac{r}{\sqrt{2}}\right)}
Hence the point is \mathrm{(2-2 \sqrt{2},-3-2 \sqrt{2})}
Hence (A) is the correct answer.

 

 

Posted by

Suraj Bhandari

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in
anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question