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If a,b,c are in AP then which of the following is an AP
Option: 1
$\frac{1}{bc},\frac{1}{ac},\frac{1}{ab}$

Option: 2
$2a.2b,2c$

Option: 3
$c,b,a$

Option: 4
$a-d,b,c+d\left ( d\neq 0 \right )$

Answers (1)

best_answer

(A) a,b,c are in AP

$\rightarrow \frac{a}{abc},\frac{b}{abc},\frac{c}{abc}$ are in AP

(dividing by same term gives a new AP)

(B) a,b,c are in AP

$\rightarrow 2a,2b,2c$ are in AP

(multiplying by same term gives a new AP)

(C) a,b,c are in AP

$\rightarrow c,b,a$ are in AP

(Reverse of an AP is also an AP)

So, (D) is not an AP

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Ritika Jonwal

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