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  • If at a point on boundary between two dielectric the electric field make angle and <img alt="\theta_2" src="h

If at a point on boundary between two dielectric the electric field make angle \theta_1 and \theta_2 with the normal in media of permittivity \epsilon_1 and \epsilon_2 respectively, then which one of the relation is correct?

Option: 1

\mathrm{\frac{\tan \theta_1}{\tan \theta_2}=\frac{\epsilon_1}{\epsilon_2}}


Option: 2

\mathrm{\frac{\tan \theta_1}{\tan \theta_2}=\frac{\epsilon_2}{\epsilon_1}}


Option: 3

\mathrm{\frac{\sin \theta}{\sin \theta_2}=\frac{\epsilon_1}{\epsilon_2}}


Option: 4

\mathrm{\frac{\sin \theta_1}{\sin \theta_2}=\frac{\epsilon_2}{\epsilon_1}}


Answers (1)

best_answer

\mathrm{\begin{aligned} D_1 \cos \theta_1 & =D_2 \cos \theta_2 \\ \epsilon_1 E_1 \cos \theta_1 & =\epsilon_2 E_2 \cos \theta_2.........\left ( 1 \right ) \end{aligned}}
Tangential component of electric intensity is continuous across boundary -
\mathrm{Divide\ (2)\ by\ (1)}
\mathrm{ \\ \begin{gathered} \frac{\tan \theta_1}{\epsilon_1}=\frac{\tan \theta_2}{\epsilon_2} \\ \frac{\tan \theta_1}{\tan \theta_2}=\frac{\epsilon_1}{\epsilon_2} \text {}\end{gathered}}   


                  

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vinayak

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