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If chord AB of circle \mathrm{x^2+y^2=16}, passing through \mathrm{(\sqrt{6},-\sqrt{6})} and inclined at angle \mathrm{135^{\circ}} with x-axis the equation of circle with AB as diameter will be 

 

Option: 1

\mathrm{x^2+y^2=12}


Option: 2

\mathrm{x^2+y^2-2 x+6=0}


Option: 3

\mathrm{x^2+y^2-2^{\sqrt{6}} x-2 \sqrt{6} y+5=0}


Option: 4

\mathrm{x^2+y^2=16}


Answers (1)

best_answer

Equation of chord will be \mathrm{y+\sqrt{6}=-(x-\sqrt{6})}

⇒ x + y = 0

Which passing through (0, 0), so it will be diameter of the circle, so equation of required circle will be same as of given circle.

 

Posted by

shivangi.bhatnagar

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