Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

If chord AB of circle \mathrm{x^2+y^2=16}, passing through \mathrm{(\sqrt{6},-\sqrt{6})} and inclined at angle \mathrm{135^{\circ}} with x-axis the equation of circle with AB as diameter will be 

 

Option: 1

\mathrm{x^2+y^2=12}


Option: 2

\mathrm{x^2+y^2-2 x+6=0}


Option: 3

\mathrm{x^2+y^2-2^{\sqrt{6}} x-2 \sqrt{6} y+5=0}


Option: 4

\mathrm{x^2+y^2=16}


Answers (1)

best_answer

Equation of chord will be \mathrm{y+\sqrt{6}=-(x-\sqrt{6})}

⇒ x + y = 0

Which passing through (0, 0), so it will be diameter of the circle, so equation of required circle will be same as of given circle.

 

Posted by

shivangi.bhatnagar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question