Get Answers to all your Questions

header-bg qa

If (h, k) is a point on the axis of parabola 2(x-1)^2+2(y-1)^2=(x+y+2)^2  from where three distinct normals can be drawn, then

 

Option: 1

 h > 2


Option: 2

 h < 4 

 


Option: 3

h > 8


Option: 4

 h < 8


Answers (1)

best_answer

\left(\frac{x+y+2}{\sqrt{2}}\right)^2=(x-1)^2+(y-1)^2 

which is of the following P M^2=S P^2

\therefore \text { Focus }=(1,1). Directrix  is x+y+2=0

Axis isx-y=0 \text { and } z=(-1,-1)

Vertex = (0,0). Parameter a=\sqrt{2}

The distance of the point from vertex and lie on axis  from which  3  normals can be drawn must be greater 2 a=2 \sqrt{2} .Hence point on axis at a distance 2 \sqrt{2} \text { is }(2,2) Hence h>2

 

 

Posted by

Ritika Jonwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE