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If \frac{b+c-a}{a},\frac{c+a-b}{b},\frac{a+b-c}{c} are in A.P then which of the following are also in A.P?


 

 

 

Option: 1

a^2,b^2,c^2


Option: 2

\frac{1}{a},\frac{1}{b},\frac{1}{c}


Option: 3

2a,2b,2c


Option: 4

None of these


Answers (1)

best_answer

\frac{b+c-a}{a},\frac{c+a-b}{b},\frac{a+b-c}{c} are in A.P

So, \frac{b+c-a}{a}+2,\frac{c+a-b}{b}+2,\frac{a+b-c}{c}+2 are in A.P

So, \frac{b+c+a}{a},\frac{c+a+b}{b},\frac{a+b+c}{c}   are in A.P

Dividing each term by (a+b+c) will give a new AP

So, \frac{1}{a},\frac{1}{b},\frac{1}{c} is an A.P.

So (b) is correct.

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vinayak

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